Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 8 - Geometry - Test - Page 620: 24

Answer

$y = 12$ cm $z = 6$ cm

Work Step by Step

1. Solve for $y$ $\frac{10}{15} = \frac{y}{18}$ $\frac{180}{15} = y$ $y = 12$ cm 2. Solve for $z$ $\frac{10}{15} = \frac{z}{9}$ $z = \frac{90}{15}$ $z = 6$ cm
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