Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - Test - Page 620: 19


The area of the semicircle is $39.3$ m$^{2}$

Work Step by Step

1. Using the formula $\frac{1}{2} \pi r^{2}$, find the area of the semicircle Let $A= $ the area of the semi-circle $A = \frac{1}{2}\pi r^{2}$ $A = \frac{1}{2} 3.14 \times (5^{2})$ $A = \frac{1}{2} 3.14 \times 25$ $A = 39.25$ m$^{2}$ $A = 39.3$ m$^{2}$
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