Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 8 - Geometry - Test - Page 620: 21

Answer

Sphere V$\approx$33.5 ft$^3$

Work Step by Step

V=$\frac{4}{3}$(3.14)(2$^3$) V$\approx$33.5
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