Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - 8.8 Pythagorean Theorem - 8.8 Exercises - Page 592: 28

Answer

Hypotenuse $\approx 12.2$ km.

Work Step by Step

Let $H =$ hypotenuse of the triangle $a^{2} + b^{2} = c^{2}$ $7^{2} + 10^{2} = H^{2}$ $49 + 100 = H^{2}$ $149 = H^{2}$ $H = \sqrt 149$ $H = 12.206...$ $H \approx 12.2$ km
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