## Basic College Mathematics (10th Edition)

Hypotenuse $\approx 11.7$ yd.
Let $H =$ hypotenuse of the triangle $a^{2} + b^{2} = c^{2}$ $4^{2} + 11^{2} = H^{2}$ $16 + 121 = H^{2}$ $137 = H^{2}$ $H = \sqrt 137$ $H = 11.704...$ $H \approx 11.7$ yd