## Basic College Mathematics (10th Edition)

Hypotenuse $\approx 12.1$ cm.
Let $H =$ hypotenuse of the triangle $a^{2} + b^{2} = c^{2}$ $5^{2} + 11^{2} = H^{2}$ $25 + 121 = H^{2}$ $146 = H^{2}$ $H = \sqrt 146$ $H = 12.083...$ $H \approx 12.1$ cm