## Basic College Mathematics (10th Edition)

$A$ = 1674.2 ft$^{2}$ $P$ = 196.2 ft
Since the length and width of the object are different it is a rectangle. Area of a rectangle: $A$ = $l$ * $w$ $A$ = 76.1 ft * 22 ft $A$ = 1674.2 ft$^{2}$ Perimeter of a rectangle: $P$ = 2$l$ + 2$w$ $P$ = 2(76.1 ft) + 2(22 ft) $P$ = 152.2 ft + 44 ft $P$ = 196.2 ft