Basic College Mathematics (10th Edition)

$A$= 144 m$^{2}$ $P$ = 48 m
Since the length and the width of the lab are the same it is a square. Area of a Square: $A$ = $s$$^{2}$ $A$ = (12 m)$^{2}$ $A$ = 144 m$^{2}$ Perimeter of a Square: $P$ = 4$s$ $P$ = 4(12 m) $P$ = 48 m