Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises - Page 550: 7

Answer

$A$ = 100 ft$^{2}$ $P$ = 40 ft

Work Step by Step

Since the length and width of this object are same it is a square. Area of a square: $A$=$s$$^{2}$ $A$ = (10 ft)$^{2}$ $A$ = 100 ft$^{2}$ Perimeter of a square: $P$ = 4$s$ $P$ = 4 * 10 ft $P$ = 40 ft
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