## Basic College Mathematics (10th Edition)

$1\frac{1}{3}$
$\frac{5}{6}+\frac{4}{3}.(\frac{3}{8})$ = $\frac{5}{6}+\frac{4}{3}\times\frac{3}{8}$ (First Solve Bracket) = $\frac{5}{6}+\frac{1}{2}$ = $\frac{5}{6}+\frac{1\times3}{2\times3}$ (Least common multiple of 6 & 2 is 6) = $\frac{5}{6}+\frac{3}{6}$ = $\frac{5+3}{6}$ = $\frac{8}{6}$ = $\frac{4}{3}$ = $1\frac{1}{3}$