Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - Test - Page 260: 21



Work Step by Step

$\frac{19}{24}$_$\frac{17}{36}$ Now to compare the fractions we need to have same denominators. $\frac{19\times3}{24\times3}$ & $\frac{17\times2}{36\times2}$ (Least common multiple of 24 & 36 is 72) = $\frac{57}{72}$ & $\frac{34}{72}$ Now $\frac{57}{72}\gt\frac{34}{72}$ i.e. $\frac{19}{24}\gt\frac{17}{36}$
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