Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 3 - Adding and Subtracting Fractions - Test - Page 260: 21

Answer

$\frac{19}{24}\gt\frac{17}{36}$

Work Step by Step

$\frac{19}{24}$_$\frac{17}{36}$ Now to compare the fractions we need to have same denominators. $\frac{19\times3}{24\times3}$ & $\frac{17\times2}{36\times2}$ (Least common multiple of 24 & 36 is 72) = $\frac{57}{72}$ & $\frac{34}{72}$ Now $\frac{57}{72}\gt\frac{34}{72}$ i.e. $\frac{19}{24}\gt\frac{17}{36}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.