Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 3 - Adding and Subtracting Fractions - Test - Page 260: 24

Answer

$1\frac{3}{4}$

Work Step by Step

$4(\frac{7}{8}-\frac{7}{16})$ = $4(\frac{7\times2}{8\times2}-\frac{7}{16})$ (First Solve Bracket) = $4(\frac{14}{16}-\frac{7}{16})$ = $4(\frac{14-7}{16})$ = $4(\frac{7}{16})$ = $4\times\frac{7}{16}$ = $\frac{7}{4}$ = $1\frac{3}{4}$
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