Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - Test - Page 260: 24



Work Step by Step

$4(\frac{7}{8}-\frac{7}{16})$ = $4(\frac{7\times2}{8\times2}-\frac{7}{16})$ (First Solve Bracket) = $4(\frac{14}{16}-\frac{7}{16})$ = $4(\frac{14-7}{16})$ = $4(\frac{7}{16})$ = $4\times\frac{7}{16}$ = $\frac{7}{4}$ = $1\frac{3}{4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.