Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.5 Order Relation and the Order of Operations - 3.5 Exercises - Page 244: 49



Work Step by Step

$6(\frac{2}{3})^{2}(\frac{1}{2})^{2}$ = $6(\frac{2}{3})(\frac{2}{3})(\frac{1}{2})(\frac{1}{2})$ = $(\frac{6}{1})(\frac{1}{3})(\frac{1}{3})(\frac{1}{1})(\frac{1}{1})$ = $\frac{6}{9}$ = $\frac{2}{3}$
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