Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.5 Order Relation and the Order of Operations - 3.5 Exercises - Page 244: 48

Answer

$\frac{1}{100}$

Work Step by Step

$(\frac{5}{8})^{2} \times (\frac{4}{25})^{2}$ = $\frac{5}{8} \times \frac{5}{8} \times\frac{4}{25} \times \frac{4}{25}$ = $\frac{1}{2} \times \frac{1}{2} \times\frac{1}{5} \times \frac{1}{5}$ = $\frac{1}{100}$
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