Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.5 Order Relation and the Order of Operations - 3.5 Exercises - Page 244: 47



Work Step by Step

$(\frac{4}{5})^{2} \times (\frac{5}{6})^{2}$ = $\frac{16}{25} \times \frac{25}{36}$ = $\frac{4}{1} \times \frac{1}{9}$ = $\frac{4}{9}$
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