Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.4 Adding and Subtracting Mixed Numbers - 3.4 Exercises - Page 229: 50

Answer

$8\frac{2}{15}$

Work Step by Step

$2\frac{4}{5}$ + $5\frac{1}{3}$ = $\frac{14}{5}$ + $\frac{16}{3}$ = $\frac{42}{15}$ + $\frac{80}{15}$ = $\frac{122}{15}$ = $8\frac{2}{15}$
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