Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 3 - Adding and Subtracting Fractions - 3.4 Adding and Subtracting Mixed Numbers - 3.4 Exercises - Page 229: 45

Answer

$11\frac{1}{2}$

Work Step by Step

$4\frac{2}{3}$ + $6\frac{5}{6}$ = $\frac{14}{3}$ + $\frac{41}{6}$ = $\frac{28}{6}$ + $\frac{41}{6}$ = $\frac{69}{6}$ = $11\frac{3}{6}$ = $11\frac{1}{2}$
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