Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 3 - Adding and Subtracting Fractions - 3.4 Adding and Subtracting Mixed Numbers - 3.4 Exercises - Page 229: 49

Answer

$6\frac{11}{12}$

Work Step by Step

$3\frac{1}{4}$ + $3\frac{2}{3}$ = $\frac{13}{4}$ + $\frac{11}{3}$ = $\frac{39}{12}$ + $\frac{44}{12}$ = $\frac{83}{12}$ = $6\frac{11}{12}$
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