Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.1 Adding and Subtracting Like Fractions - 3.1 Execises - Page 201: 32

Answer

$\frac{3}{2}$

Work Step by Step

$\frac{181}{100}-\frac{31}{100}=\frac{181-31}{100}=\frac{150}{100}=\frac{150\div50}{100\div50}=\frac{3}{2}$
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