Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.1 Adding and Subtracting Like Fractions - 3.1 Execises - Page 201: 27

Answer

$\frac{1}{5}$

Work Step by Step

$\frac{27}{40}-\frac{19}{40}=\frac{27-19}{40}=\frac{8}{40}=\frac{8\div8}{40\div8}=\frac{1}{5}$
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