Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.1 Adding and Subtracting Like Fractions - 3.1 Execises - Page 201: 23

Answer

$\frac{3}{5}$

Work Step by Step

$\frac{9}{10}-\frac{3}{10}=\frac{9-3}{10}=\frac{6}{10}=\frac{6\div2}{10\div2}=\frac{3}{5}$
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