Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - 8-6 Law of Cosines - Practice and Problem-Solving Exercises - Page 530: 8

Answer

$m \angle W \approx 40.3^{\circ}$

Work Step by Step

First, we want to know what angle is opposite the side in question. The side that is opposite to the angle we are looking for is $\overline{XY}$, so let's plug in what we know into the formula for the law of cosines: $16.4^2 = 25.3^2 + 20.4^2 - 2(25.3)(20.4)$ cos $\angle W$ Evaluate exponents first, according to order of operations: $268.96 = 640.09 + 416.16 - 2(25.3)(20.4)$ cos $m \angle W$ Add to simplify on the right side of the equation: $268.96 = 1056.25 - 2(25.3)(20.4)$ cos $m \angle W$ Multiply to simplify: $268.96 = 1056.25 - 1032.24$ cos $m \angle W$ Subtract $1056.25$ from each side of the equation to move constants to the left side of the equation: $-787.29 = -1032.24$ cos $m \angle W$ Divide each side by $-1032.24$: cos $m \angle W$ \approx $0.7627$ Take $cos^{-1}$ to solve for $\angle W$: $m \angle W \approx 40.3^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.