Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - 8-3 Trigonometry - Practice and Problem-Solving Exercises - Page 511: 34

Answer

$w = 6.7$ $x = 8.1$

Work Step by Step

Since we have the measure of an angle and the measure of the opposite side, we can use the tangent ratio to find $w$, which is the side adjacent to the given angle. The tangent ratio is given as follows: tan $A = \frac{opposite}{adjacent}$ Let's plug in what we know: tan $56^{\circ} = \frac{10}{w}$ Multiply each side by $w$: $w(tan 56^{\circ}) = 10$ Divide each side by tan $56^{\circ}$: $w = 10$/tan $56^{\circ}$ Divide to solve: $w = 6.7$ We have a bigger right triangle where we are given the measure of the angle and the side opposite. We are asked to find a segment of the adjacent side marked $x$. The adjacent side for this angle is made up of $w$, which we already found, and $x$, which we need to find. Let's use the tangent ratio again: tan $A = \frac{opposite}{adjacent}$ Let's plug in what we know: tan $A = \frac{10}{6.7 + x}$ Multiply each side by $6.7 + x$ $(tan 34^{\circ}){6.7 + x} = 10$ Divide both sides by tan $34^{\circ}$: $6.7 + x = 10$/tan $34^{\circ}$ Subtract $6.7$ from each side of the equation to isolate $x$: $x = 10$/tan $34^{\circ} - 6.7$ Do the division first: $x = 14.8 - 6.7$ Subtract to solve for $x$: $x = 8.1$
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