Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - 8-3 Trigonometry - Practice and Problem-Solving Exercises - Page 511: 33

Answer

$w = 3$ $x = 41^{\circ}$

Work Step by Step

Since we have the measure of one angle and the measure of the hypotenuse, we can use the sine ratio to find $w$, which is the side opposite to the given angle. The sine ratio is given as follows: sin $A = \frac{opposite}{hypotenuse}$ Let's plug in what we know: $\frac{x}{y} = \frac{w}{6}$ Multiply each side by $6$: $w$ = sin $30^{\circ}(6)$ Find sin $30^{\circ}$: $w = (0.5)(6)$ Multiply to solve: $w = 3$ We have another right triangle because we have a transversal cutting two parallel lines, meaning alternate interior angles are congruent. One of the alternate interior angles is a right angle in a right triangle; therefore, the other alternate interior angle is also a right angle in a triangle. In this other right triangle, we just found the measure of $w$, which is the adjacent side, and we are given the value of the hypotenuse. We can set up the ratio for cosine to find the value of angle $x$. The cosine ratio is as follows: cos $A = \frac{adjacent}{hypotenuse}$ Let's plug in our givens: cos $x = \frac{3}{4}$ Take $cos^{-1}$ of the fraction: $x = 41^{\circ}$
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