Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - 8-3 Trigonometry - Practice and Problem-Solving Exercises - Page 511: 35

Answer

$w = 68^{\circ}$ $x = 151.6$

Work Step by Step

Since we have the measure of an angle and the measure of the hypotenuse, we can use the sine ratio to find $w$, which is the side opposite to the given angle. The sine ratio is given as follows: sin $A = \frac{opposite}{hypotenuse}$ Let's plug in what we know: sin $42^{\circ} = \frac{w}{102}$ Multiply each side by $102$: $102(sin 42^{\circ}) = w$ Multiply to solve for $w$: $w = 68^{\circ}$ With the other right triangle, we are given the measure of the angle and the hypotenuse. We are asked to find half of the adjacent side marked $x$, which is the adjacent side of this particular right triangle. Let's use the cosine ratio: cos $A = \frac{adjacent}{hypotenuse}$ Let's plug in what we know: cos $42^{\circ}$ = $\frac{x/2}{102}$ Multiply each side by $102$: (cos $42^{\circ}$)$(102) = x/2$ Multiply each side by $2$: $x = 2 (cos $42^{\circ}$)$(102)$ Evaluate to solve for $x$: $x = 151.6$
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