Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 6 - Polygons and Quadrilaterals - 6-4 Properties of Rhombuses, Rectangles, and Squares - Practice and Problem-Solving Exercises - Page 379: 12

Answer

$m \angle 3 = 113^{\circ}$ $m \angle 1 = 33.5^{\circ}$ $m \angle 2 = 33.5^{\circ}$ $m \angle 3 = 33.5^{\circ}$

Work Step by Step

In parallelograms, opposite angles are congruent; therefore, $m \angle 3$ is $113^{\circ}$. In parallelograms, consecutive angles are supplementary, so $m \angle 1$, $m \angle 2$, and $m \angle 4$ are half of one of the consecutive angles. If we find the measure of a consecutive angle, we can find the measures of $\angle 1$, $\angle 2$, and $\angle 4$. Let's find the measure of one of the consecutive angles: $m$ consecutive angle = $180 - 113$ Subtract to solve: $m$ consecutive angle = $67$ If we divide this consecutive angle by $2$, then we will get $m \angle 1$, $m \angle 2$, and $m \angle 4$: $m \angle 1 = m \angle 2 = m \angle 3 = 67/2$ Divide to solve: $m \angle 1 = m \angle 2 = m \angle 3 = 33.5^{\circ}$
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