Answer
$m \angle 1 = 26^{\circ}$
$m \angle 2 = 128^{\circ}$
$m \angle 3 = 128^{\circ}$
Work Step by Step
Diagonals of rhombuses bisect pairs of opposite angles, so if we double $26^{\circ}$, then we will get one of the opposite angles:
$m$ opposite angle = $2(26)$
Multiply to solve:
$m$ opposite angle = $52$
The other opposite angle would also be bisected by that same diagonal, so $m \angle 1$ is also $26$.
$\angle 2$ and $\angle 3$ are congruent but supplementary to the opposite angle that has a measure of $52^{\circ}$.
$m \angle 2 = m \angle 3 = 180 - 52$
Subtract to solve:
$m \angle 2 = m \angle 3 = 128$
