Answer
$m \angle 1 = 118^{\circ}$
$m \angle 2 = 31^{\circ}$
$m \angle 3 = 31^{\circ}$
Work Step by Step
In parallelograms, opposite angles are congruent; therefore, $m \angle 1$ is $118^{\circ}$.
In parallelograms, consecutive angles are supplementary, so $\angle 2$ and $\angle 3$ are half of one of the consecutive angles. If we find the measure of a consecutive angle, we can find the measure of both $\angle 2$ and $\angle 3$. Let's find the measure of one of the consecutive angles:
$m$ consecutive angle = $180 - 118$
Subtract to solve:
$m$ consecutive angle = $62$
If we divide this consecutive angle by $2$, then we will get $m \angle 2$ and $m \angle 3$:
$m \angle 2 = m \angle 3 = 62/2$
Divide to solve:
$m \angle 2 = m \angle 3 = 31^{\circ}$
