Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-4 Perimeters and Areas of Similar Figures - Practice and Problem-Solving Exercises - Page 639: 15


59 $ft^{2}$

Work Step by Step

Find the ratio of corresponding sides. $\frac{16}{12}$=$\frac{4}{3}$ The ratio of the areas is the square of the ratio of corresponding sides. $\frac{4^{2}}{3^{2}}$=$\frac{16}{9}$ Set up a proportion using the ratio of the areas found above. $\frac{16}{9}$=$\frac{105}{A}$ Cross multiply. 16A=9(105) 16A=905 Divide both sides by 16. A=59.0625 Area is approximately 59.
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