Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-4 Perimeters and Areas of Similar Figures - Practice and Problem-Solving Exercises - Page 639: 24

Answer

$\dfrac{1}{10}$ and $1: 10$

Work Step by Step

We can see that the ratio of the perimeters of two smaller figures is $\dfrac{a}{b}$, and the ratio of their areas is the square of the ratio of their perimeters: $\dfrac{a^2}{b^2}$. Set up a proportion: $\dfrac{a^2}{b^2}=\dfrac{2\pi}{200 \pi} \\ \dfrac{a}{b}=\sqrt {\dfrac{2\pi}{200 \pi}}=\sqrt {\dfrac{1}{100}}$ This implies that the square factor is $ \dfrac{a}{b}=\dfrac{1}{10}$ So, the ratio of the perimeters is equal to the scale factor, which is $1:10$.
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