Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-4 Perimeters and Areas of Similar Figures - Practice and Problem-Solving Exercises: 14

Answer

54 $m^{2}$

Work Step by Step

Find the ratio of corresponding sides. $\frac{12}{18}$=$\frac{2}{3}$ The ratio of the areas is the square of the ratio of corresponding sides. $\frac{2^{2}}{3^{2}}$=$\frac{4}{9}$ Set up a proportion using the ratio of the areas found above. $\frac{4}{9}$=$\frac{A}{121}$ Cross multiply: 9A=4(121) 9A=484 Divide both sides by 9: A=53.7777 Area is approx 54.
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