Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-4 Perimeters and Areas of Similar Figures - Practice and Problem-Solving Exercises - Page 638: 13


24 $in^{2}$

Work Step by Step

The ratio of the areas is the square of the ratio of corresponding sides $\frac{3^{2}}{6^{2}}$=$\frac{9}{36}$ Set up a proportion using the ratio of the areas found above: $\frac{9}{36}$=$\frac{6}{A}$ Cross multiply 9A=6(36) 9A=216 Divide both sides by 9 A=24
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