Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 9 - Section 9.3 - Cylinders and Cones - Exercises: 9

Answer

r= 2 in. h= 3 in.

Work Step by Step

Lateral area = 2 $\times$ $\pi$ $\times$ r $\times$ h 12 $\pi$ = 2 $\times$ $\pi$ $\times$ r $\times$ (r+1) 6 = $r^{2}$ + r $r^{2}$ + r - 6 = 0 r = $\frac{-b + \sqrt (b^{2} - 4 ac)}{2a}$ a= 1 b= 1 c=-6 r = 2 in. h = 2 in + 1 in. = 3 in.
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