Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 9 - Section 9.3 - Cylinders and Cones - Exercises: 8

Answer

4 in.

Work Step by Step

diameter = 2 r = $\frac{3}{4}$ h r = $\frac{3}{8}$ h Volume = $\pi$ $r^{2}$ h 9 $\pi$ $in.^{3}$ = $\pi$ $(\frac{3}{8} h)^{2}$ h 9 $\pi$ $in.^{3}$ = $\frac{9}{64}$ $\pi$ $h^{3}$ $h^{3}$ = 64 $in.^{3}$ h = 4 in.
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