Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 9 - Section 9.3 - Cylinders and Cones - Exercises: 3b

Answer

= 110 $\pi$ $in.^{2}$ $\approx$ 345,6 $in.^{2}$

Work Step by Step

Base area = $\pi$ $r^{2}$ Base area = 25 $\pi$ $in.^{2}$ Lateral area = 2 $\times$ $\pi$ $\times$ r $\times$ h Lateral area = 2 $\times$ $\pi$ $\times$ 5 in. $\times$ 6 in. Lateral area = 60 $\pi$ $in.^{2}$ Total area = 2 $\times$ base area + lateral area Total area = 2 $\times$ 25 $\pi$ $in.^{2}$ + 60 $\pi$ $in.^{2}$ Total area = 110 $\pi$ $in.^{2}$ $\approx$ 345,6 $in.^{2}$
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