Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 8 - Section 8.1 - Area and Initial Postulates - Exercises - Page 359: 16

Answer

110 $ft^{2}$

Work Step by Step

We need to find the area of the given figure Area of pentagon = area of rectangle + area of triangle Area of rectangle whose base has length b and height has length h is given by A =bh From the given diagram b= 10 ft h = 9 ft Area of rectangle = bh = 10 ft * 9 ft = 90 $ft^{2}$ Area of triangle whose base has length b and altitude has length h is given by A = $\frac{1}{2}$ bh From given diagram base b = 10 ft h = 13 -9 = 4 ft Area = $\frac{1}{2}$ * 10 * 4 = 20 $ft^{2}$ Therefore the area of Pentagon = area of triangle + area of rectangle = 90 + 20 = 110 $ft^{2}$ Therefore the area of the given figure = 110 $ft^{2}$
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