Answer
13.245 $yd^{2}$
Work Step by Step
From the given figure , We need to find out the area of the parallelogram EFGH
First convert all the measurement into same units
Lets take HE = 10 ft
1 ft = 0.33 yd
so 10 ft = 10 * 0.33yd = 3.32 yd
By Pythagoras theorem in parallelogram EFGH
$(10 ft)^{2}$ = $(2 yd)^{2}$ + $altitude^{2}$
$(3.32 yd)^{2}$ = $(2 yd)^{2}$ + $altitude^{2}$
$altitude^{2}$ = $(3.32 yd)^{2}$ - $(2 yd)^{2}$
= 11.0224 - 4
= 7.022
altitude = $\sqrt 7.022$
= 2.649 yd
By theorem 8.1.2 The area A of a parallelogram with a base of length b and corresponding altitude of length h is given by A=bh
From the given figure base b = 2+3 = 5 yd
altitude = 2.649 yd
therefore area of parallelogram = bh
= 5 * 2.649 yd = 13.245 $yd^{2}$
