Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 6 - Section 6.1 - Circles and Related Segments and Angles - Exercises - Page 286: 9c

Answer

$m\widehat {BC}=135^{\circ}$

Work Step by Step

If the $m\widehat {ACB}=270^{\circ}$, and point $C$ bisects arc $ACB$, then $m\widehat {BC}$ is half the $m\widehat {ACB}$ or $m\widehat {BC}=135^{\circ}$.
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