#### Answer

RV=$\sqrt 33$

#### Work Step by Step

Given SR=3, RQ=4, therefore QS=QV=7 as radians of the circle.
$\triangle$ QRV is right triangle with $\angle$ R =90$^{\circ}$.
By using theorem phytogoras,
$QV^{2}$=$RV^{2}$ + $RQ^{2}$
$7^{2}$=$RV^{2}$ + $4^{2}$
$RV^{2}$=33
RV=$\sqrt 33$