Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 6 - Section 6.1 - Circles and Related Segments and Angles - Exercises: 16a

Answer

RV=$\sqrt 33$

Work Step by Step

Given SR=3, RQ=4, therefore QS=QV=7 as radians of the circle. $\triangle$ QRV is right triangle with $\angle$ R =90$^{\circ}$. By using theorem phytogoras, $QV^{2}$=$RV^{2}$ + $RQ^{2}$ $7^{2}$=$RV^{2}$ + $4^{2}$ $RV^{2}$=33 RV=$\sqrt 33$
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