## Elementary Geometry for College Students (5th Edition)

RV=$\sqrt 33$
Given SR=3, RQ=4, therefore QS=QV=7 as radians of the circle. $\triangle$ QRV is right triangle with $\angle$ R =90$^{\circ}$. By using theorem phytogoras, $QV^{2}$=$RV^{2}$ + $RQ^{2}$ $7^{2}$=$RV^{2}$ + $4^{2}$ $RV^{2}$=33 RV=$\sqrt 33$