Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 6 - Section 6.1 - Circles and Related Segments and Angles - Exercises: 11g

Answer

$m\angle 4=10^{\circ}$

Work Step by Step

In part f we determined that the $m\angle 3=160^{\circ}$. All radii of a circle are congruent, therefore $\overline{CQ}=\overline{AQ}$, creating an isosceles triangle. The two base angles of an isosceles triangle are congruent. So if we subtract the vertex angle ($\angle 3$) from $180^{\circ}$ and then divide the resulting number by two (two base angles), we will find the measure of the missing angle. $180-160=20\div2=10$ $m\angle 4=10^{\circ}$
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