Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 5 - Section 5.6 - Segments Divided Proportionally - Exercises - Page 266: 11

Answer

x=5 AD=4

Work Step by Step

$\frac{AD}{AE}$=$\frac{DB}{EC}$ $\frac{a-1}{a}$=$\frac{2a+2}{4a-5}$ 4a$^2$-5a-4a+5=2a$^2$+2a 2a$^2$-11a+5=0 (2x-1)(x-5)=0 x=5 because x$\gt$1 (see AD) AD=x-1=4
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