Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 5 - Section 5.6 - Segments Divided Proportionally - Exercises - Page 266: 7

Answer

x=5$\frac{1}{3}$ DE=5$\frac{1}{3}$ EF=6$\frac{2}{3}$

Work Step by Step

$\frac{AB}{DE}$=$\frac{BC}{EF}$ $\frac{4}{x}$=$\frac{5}{12-x}$ 48-4x=5x 9x=48 x=5$\frac{1}{3}$ DE=x=5$\frac{1}{3}$ EF=12-5$\frac{1}{3}$ EF=6$\frac{2}{3}$
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