Answer
x=7
BC=7
DE=5
Work Step by Step
$\frac{AB}{DE}$=$\frac{BC}{EF}$
$\frac{5}{x-2}$=$\frac{x}{7}$
x$^2$-2x-35=0
(x-7)(x+5)=0
x=7
BC=x=7
DE=x-2
DE=7-2=5
Elementary Geometry for College Students (5th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
1439047901
ISBN 13:
978-1-43904-790-3
Chapter 5 - Section 5.6 - Segments Divided Proportionally - Exercises - Page 266: 8
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