Answer
44.3
Work Step by Step
We first need to solve for the height:
$h=5sin70^{\circ} = 4.69$
We also need to find the length of the missing base:
$l = 6+ 5cos70^{\circ} + 7cos42^{\circ}=12.91$
Thus, we find the area:
$A = (1/2)(b_1+b_2)(h) = (1/2)(12.91 + 6)(4.69) = 44.3$
