Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises: 3a


$\frac{sine 40°}{5}$ = $\frac{sine β}{8}$

Work Step by Step

Given a=5 b=8 and α =40° By law of sines $\frac{sine α}{a}$ = $\frac{sine β}{b}$ $\frac{sine 40°}{5}$ = $\frac{sine β}{8}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.