Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 527: 17

Answer

$11.1$ in.

Work Step by Step

$\frac{\sin70^{\circ}}{12}=\frac{\sin60^{\circ}}{x}$ $\sin70^{\circ}x=12\sin60^{\circ}$ $x=\frac{12\sin60^{\circ}}{\sin70^{\circ}}$ $x\approx11.1$
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