Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 10 - Section 10.2 - Graphs of Linear Equations and Slope - Exercises - Page 466: 44

Answer

$A=(1/2)(ma+b)(a)(a+\frac{b}{m})$

Work Step by Step

The length of the first base is a. The length of the second base is equal to a plus the x-intercept. Thus, this is given by: $ a + \frac{b}{m}$. Finally, the height is the y-value where the two lines intersect, which is: $ y = ma + b$ Thus, the equation is: $A = (1/2)(h)(b_1+b_2) = (1/2)(ma+b)(a)(a+\frac{b}{m})$
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