Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 10 - Section 10.2 - Graphs of Linear Equations and Slope - Exercises - Page 466: 43

Answer

$-\frac{b^2}{2m}$

Work Step by Step

The height of the triangle is b. Thus, we must find the base. Since the line starts at b and goes down at a rate of m, it will intersect the x-axis at $x=-\frac{b}{m}$. Thus, the area is: $A = (1/2)(base)(h) = b(-\frac{b}{m})(1/2) = -\frac{b^2}{2m}$
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