## Elementary Geometry for College Students (5th Edition)

$(5,\pm\frac{16}{3})$
We plug in 5 for x, and then we solve for the corresponding y point that is that far away: $\sqrt{100 + y^2} = \mid{y}\mid +6 \\ 100 + y^2 = 36 + y^2 + 12\mid y \mid \\ 12 \mid y \mid = 64 \\ y = \pm \frac{16}{3}$ After finding these points, plot them on the graph. Once the points have been plotted on the graph, connect them using curvy lines (similar to those of parabolas).