Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 10 - Section 10.1 - The Rectangular Coordinate System - Exercises - Page 457: 38b



Work Step by Step

Since the cross section consists of two of the triangles, we find the equation for volume: $V = (2/3)(\pi)(r^2)(h)$ We know that the values of 6 are what are being rotated, so we obtain that r=6. Thus: $V = (2/3)(\pi)(6^2)(4) = 96\pi$
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